Optimal. Leaf size=193 \[ \frac{2 (21 A+18 B+16 C) \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{105 a d}-\frac{4 (21 A+18 B+16 C) \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{315 d}+\frac{2 a (21 A+18 B+16 C) \tan (c+d x)}{45 d \sqrt{a \sec (c+d x)+a}}+\frac{2 a (9 B+C) \tan (c+d x) \sec ^3(c+d x)}{63 d \sqrt{a \sec (c+d x)+a}}+\frac{2 C \tan (c+d x) \sec ^3(c+d x) \sqrt{a \sec (c+d x)+a}}{9 d} \]
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Rubi [A] time = 0.473151, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.116, Rules used = {4088, 4016, 3800, 4001, 3792} \[ \frac{2 (21 A+18 B+16 C) \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{105 a d}-\frac{4 (21 A+18 B+16 C) \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{315 d}+\frac{2 a (21 A+18 B+16 C) \tan (c+d x)}{45 d \sqrt{a \sec (c+d x)+a}}+\frac{2 a (9 B+C) \tan (c+d x) \sec ^3(c+d x)}{63 d \sqrt{a \sec (c+d x)+a}}+\frac{2 C \tan (c+d x) \sec ^3(c+d x) \sqrt{a \sec (c+d x)+a}}{9 d} \]
Antiderivative was successfully verified.
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Rule 4088
Rule 4016
Rule 3800
Rule 4001
Rule 3792
Rubi steps
\begin{align*} \int \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\frac{2 C \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{9 d}+\frac{2 \int \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \left (\frac{3}{2} a (3 A+2 C)+\frac{1}{2} a (9 B+C) \sec (c+d x)\right ) \, dx}{9 a}\\ &=\frac{2 a (9 B+C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{9 d}+\frac{1}{21} (21 A+18 B+16 C) \int \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \, dx\\ &=\frac{2 a (9 B+C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{9 d}+\frac{2 (21 A+18 B+16 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{105 a d}+\frac{(2 (21 A+18 B+16 C)) \int \sec (c+d x) \left (\frac{3 a}{2}-a \sec (c+d x)\right ) \sqrt{a+a \sec (c+d x)} \, dx}{105 a}\\ &=\frac{2 a (9 B+C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}-\frac{4 (21 A+18 B+16 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 d}+\frac{2 C \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{9 d}+\frac{2 (21 A+18 B+16 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{105 a d}+\frac{1}{45} (21 A+18 B+16 C) \int \sec (c+d x) \sqrt{a+a \sec (c+d x)} \, dx\\ &=\frac{2 a (21 A+18 B+16 C) \tan (c+d x)}{45 d \sqrt{a+a \sec (c+d x)}}+\frac{2 a (9 B+C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}-\frac{4 (21 A+18 B+16 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 d}+\frac{2 C \sec ^3(c+d x) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{9 d}+\frac{2 (21 A+18 B+16 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{105 a d}\\ \end{align*}
Mathematica [A] time = 1.84672, size = 153, normalized size = 0.79 \[ \frac{\tan \left (\frac{1}{2} (c+d x)\right ) \sec ^4(c+d x) \sqrt{a (\sec (c+d x)+1)} (2 (63 A+99 B+88 C) \cos (c+d x)+11 (21 A+18 B+16 C) \cos (2 (c+d x))+42 A \cos (3 (c+d x))+42 A \cos (4 (c+d x))+189 A+36 B \cos (3 (c+d x))+36 B \cos (4 (c+d x))+162 B+32 C \cos (3 (c+d x))+32 C \cos (4 (c+d x))+214 C)}{315 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.37, size = 171, normalized size = 0.9 \begin{align*} -{\frac{ \left ( -2+2\,\cos \left ( dx+c \right ) \right ) \left ( 168\,A \left ( \cos \left ( dx+c \right ) \right ) ^{4}+144\,B \left ( \cos \left ( dx+c \right ) \right ) ^{4}+128\,C \left ( \cos \left ( dx+c \right ) \right ) ^{4}+84\,A \left ( \cos \left ( dx+c \right ) \right ) ^{3}+72\,B \left ( \cos \left ( dx+c \right ) \right ) ^{3}+64\,C \left ( \cos \left ( dx+c \right ) \right ) ^{3}+63\,A \left ( \cos \left ( dx+c \right ) \right ) ^{2}+54\,B \left ( \cos \left ( dx+c \right ) \right ) ^{2}+48\,C \left ( \cos \left ( dx+c \right ) \right ) ^{2}+45\,B\cos \left ( dx+c \right ) +40\,C\cos \left ( dx+c \right ) +35\,C \right ) }{315\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}\sin \left ( dx+c \right ) }\sqrt{{\frac{a \left ( \cos \left ( dx+c \right ) +1 \right ) }{\cos \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.505792, size = 343, normalized size = 1.78 \begin{align*} \frac{2 \,{\left (8 \,{\left (21 \, A + 18 \, B + 16 \, C\right )} \cos \left (d x + c\right )^{4} + 4 \,{\left (21 \, A + 18 \, B + 16 \, C\right )} \cos \left (d x + c\right )^{3} + 3 \,{\left (21 \, A + 18 \, B + 16 \, C\right )} \cos \left (d x + c\right )^{2} + 5 \,{\left (9 \, B + 8 \, C\right )} \cos \left (d x + c\right ) + 35 \, C\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{315 \,{\left (d \cos \left (d x + c\right )^{5} + d \cos \left (d x + c\right )^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \left (\sec{\left (c + d x \right )} + 1\right )} \left (A + B \sec{\left (c + d x \right )} + C \sec ^{2}{\left (c + d x \right )}\right ) \sec ^{3}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 4.8382, size = 470, normalized size = 2.44 \begin{align*} \frac{2 \,{\left (315 \, \sqrt{2} A a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 315 \, \sqrt{2} B a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 315 \, \sqrt{2} C a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) -{\left (840 \, \sqrt{2} A a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 630 \, \sqrt{2} B a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 420 \, \sqrt{2} C a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) -{\left (882 \, \sqrt{2} A a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 756 \, \sqrt{2} B a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 882 \, \sqrt{2} C a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) -{\left (504 \, \sqrt{2} A a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 522 \, \sqrt{2} B a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 324 \, \sqrt{2} C a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) -{\left (147 \, \sqrt{2} A a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 81 \, \sqrt{2} B a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 107 \, \sqrt{2} C a^{5} \mathrm{sgn}\left (\cos \left (d x + c\right )\right )\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{315 \,{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a\right )}^{4} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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